Given an m x n matrix, return all elements of the matrix in spiral order.
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [1,2,3,6,9,8,7,4,5]
Input: matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
Output: [1,2,3,4,8,12,11,10,9,5,6,7]
m == matrix.lengthn == matrix[i].length1 <= m, n <= 10-100 <= matrix[i][j] <= 100When the function spiralOrder is called with the given example inputs, the expected outputs are:
[[1,2,3],[4,5,6],[7,8,9]], the output is [1,2,3,6,9,8,7,4,5].[[1,2,3,4],[5,6,7,8],[9,10,11,12]], the output is [1,2,3,4,8,12,11,10,9,5,6,7].console.log(spiralOrder([[1,2,3],[4,5,6],[7,8,9]])); // Output: [1,2,3,6,9,8,7,4,5]
console.log(spiralOrder([[1,2,3,4],[5,6,7,8],[9,10,11,12]])); // Output: [1,2,3,4,8,12,11,10,9,5,6,7]
Memory: 0
CPU: 0